![]() ![]() ![]() Since, on the right hand side of the \ axis, the \ coordinate is always positive, hence, 6 will be positive in nature.Īlso, in this question, the mirror was assumed to be the \ axis, hence, the coordinates of \ will remain the same. So, we will extend this perpendicular on the other side of the mirror i.e. The distance of an object in front of the mirror and the distance of its image behind the mirror is always equal. Here, we will not take the negative value of 6 because we are talking about length which can never be negative. The objects appear as if they are mirror reflections, with right and left reversed. Both directions on the x-axis would still need to be positive. Then, one must change the signs of each of the variables: (y,x) then becomes. y-axis, with the fusions going to the left, and the decompressions going to the right. Adding C moves the function to the left (the negative direction). A reflection can be done across the y-axis by folding or flipping an. The formula for reflecting over the line y-x first involves switching the variables: (x,y) becomes (y,x). ![]() Now, we can see from the diagram that the length of the perpendicular drawn is 6 units. We can move it left or right by adding a constant to the x-value: g(x) (x C) 2. The X-Shear preserves the Y coordinate and changes are made to X coordinates, which causes the vertical lines to tilt right or left as shown in below figure. ![]()
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